version control - git (any SCM) and compiling object files, switching branches, physiology thereof -

-

if compile branch a, switch branch b, compile, , switch branch a.

all object files touched compile of branch b have recompiled!

normally 1 not check-in object files, there seems little choice here.

what ideal working practices here?

only object files dependencies differ between 2 branches need rebuilt.

when switching branches git doesn't touch files don't differ between 2 branches.

so long have appropriate dependencies expressed or deduced in build system, incremental build after branch switch work , reasonably efficient. in many of projects switch branches , incremental builds fast , reliable.

if want work on 2 branches without wanting rebuild @ when switching branches should use second clone , work in independent working areas.

checking in object files same repository source creates them bad idea. start, allows possibility of checking in input , output inconsistent.


Comments

Post a Comment

Popular posts from this blog

javascript - Enclosure Memory Copies -

-
function myclass() { //lots , lots of vars , code here. this.bar = function() { //do numerous enclosed myclass vars } this.foo = function() { alert('hello'); //don't enclosed variables. } } each instance of myclass gets own copy of bar , foo, why prototyped methods use less memory. however, know more memory use of inner methods. it seems obvious me (1) below must true. agree? not distinct myclass instances have own distinct copies of bar, must have own distinct copies of myclass enclosure. (or else how bar method keep myclass variables straight on per instance basis?) now (2) question i'm after. since inner foo method doesn't use in myclass enclosure natural qustion is: javascript smart enough not keep myclass enclosure in memory use of foo? this depend entirely on implementation not language. naive implementations keep far more around others. answer true e.g. v8 (chrome's js engine) may not true spider...
Read more

php - Replacing tags in braces, even nested tags, with regex -

-
example preg_replace('/\{[a-za-z.,\(\)0-9]+\}/', 'replaced', 'lorem ipsum dolor sit {tag1({tag2()})}, consectetur adipiscing elit.'); the result: lorem ipsum dolor sit {tag1(replaced)}, consectetur adipiscing elit. question as can see "tag2" has been replaced, want replace "tag1" know how can this? (in cases might this: {tag1({tag2({tag3()})})}) , on.) btw using preg_replace_callback, easier show preg_replace here site can test code: http://www.spaweditor.com/scripts/regex/index.php you need add curly braces character set. here's pattern used: /\{[a-za-z.,\(\)\{\}0-9]+\}/ and here result: "lorem ipsum dolor sit replaced, consectetur adipiscing elit."
Read more