C# LINQ TimeSpan Average Days -

i learning linq , want linq query equivalent of following code.

the ienumerable list contains sorted list of dates: oldest newest.

the code below derives timespans subtracting array's zeroth element date array's first element date, first element date 2nd, 2nd 3rd , on. timespan.days averaged elsewhere in code.

i trust linq query not require construction of array. ienumerable<datetime> structure used data source.

 ienumerable<datetime> list; // contains sorted list of oldest newest dates  // build datetime array    datetime[] datesarray = null;  timespan ts;  list<int> dayslist = new list<int>();   datesarray = (from dt in list                select dt).toarray();  // loop through array , derive timespan subtracting previous date, // contained in previous array element, date in current array element. // start loop @ element 1.   (int = 1; < list.count(); i++)  {      ts = datesarray[i].subtract(datesarray[i - 1]); // ts timespan type      dayslist.add(ts.days);      // add timespan.days list<int> averaging elsewhere.  } 

thank you,

scott

i think want:

double averagedays = list                      .skip(1)                      .zip(list, (next, prev) => (double)next.subtract(prev).days)                      .average(); 

do note lossy average. sure don't want use totaldays instead?

edit:

the way works overlay sequence 'one-deferred' version of sequence, makes easy calculate consecutive deltas. it's matter of averaging deltas produce result.

for comparison, 'faithful' translation of existing code like:

double averagedays = enumerable                      .range(1, list.count - 1)                      .average(i => (double)list[i].subtract(list[i - 1]).days);