regex - How to create inverse of scrubbing script in SED? -

i wrote sed script deletes rows ("/d") match set of ip regular expressions. want re-read same source file , create inverse output - delete not in list.

if throw "!" expression, delete since match "not" condition of other ip list entries.

here's example of regex in internal.lst:

/10\.10\.50\.0/d /10\.100\.0\.0/d /10\.101\.0\.0/d /10\.101\.0\.128/d 

and example of sed execution (in .bat file):

for /f %%f in ('dir /b source\*.txt') (   sed -f ..\internal.lst staging\%%f > scrubbed\external\%%f   rem inverse of above line!!!!   >scrubbed\internal\%%f move staging\%%f scrubbed\original      ) 

edit: confirm understand bobbogo's comment, i'd like:

sed -f list.lst staging\in.txt > out.txt 

and i'll put in list.lst file:

/10\.100\.0\.0{p;n} /10\.101\.0\.0{p;n} /10\.101\.0\.128{p;n} 

is right?

in gnu sed, -n option suppresses automatic printing of pattern space, allows use p command print select lines:

$ cat in.txt  10.101.0.128 10.101.0.133 10.101.0.11 $ sed -n '/10\.10\.50\.0/p /10\.100\.0\.0/p /10\.101\.0\.0/p /10\.101\.0\.128/p' in.txt 10.101.0.128 

edit:

note approach produce duplicates if input line can match more 1 expressions:

$ cat in.txt  10.101.0.0 10.101.0.128 10.101.0.133 10.101.0.11 $ sed -n '/10\.10\.50\.0/p /10\.100\.0\.0/p /10\.101\.0\.0/p /10\.101\.0\.128/p /10\.101\.0\.[0-9]$/p' in.txt 10.101.0.0 10.101.0.0 10.101.0.128 

to deal this, can use p command, followed d command:

$ sed -n '/10\.10\.50\.0/{p; d} /10\.100\.0\.0/{p; d} /10\.101\.0\.0/{p; d} /10\.101\.0\.128/{p; d} /10\.101\.0\.[0-9]$/{p; d}' in.txt 10.101.0.0 10.101.0.128 

edit:

as per comment bobbogo, can use n command instead of d.