javascript - How to Extract/Retrieve source code given URL in Firefox extention -

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i'm writing firefox extension analyze / parse linked pages while user still on current page. know there ways retrieve source code page being viewed, linked pages? if i'm able obtain url of linking page, able retrieve source code of url?

my extension written in xul , javascript, code or sample add-ons me lot!

maybe following javascript snippet you: 

var req = new xmlhttprequest(); req.open("get", linkedpageurl, false); req.send(null); dosomethingwithgivensource(req.responsetext);

this works synchronously. after req.send(null) executed, req.responsetext contains page source code. recommended avoid synchronous network actions better approach use asynchronous request , add callback load event:

var req = new xmlhttprequest(); req.open("get", linkedpageurl, true); req.addeventlistener("load", function() {   dosomethingwithgivensource(req.responsetext); }, false); req.send(null);

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