java - Hibernate: Programmatically binding UserTypes on Components -

-

i have several different usertypes (org.hibernate.usertype.usertype) in system. question focus on fact use joda time datetime , usertype, persistentdatetime.

i have bound usertype programmatically persistentclass's by:

public void customize(ejb3configuration config) {  iterator<persistentclass> itr = config.getclassmappings();    while(itr.hasnext()) {        persistentclass persistentclass = itr.next();        for(iterator<property> iter = persistentclass.getpropertyiterator(); iter.hasnext();) {            if(property.gettype().getreturnedclass().equals(datetime.class)) {                simplevalue original = (simplevalue) property.getvalue();                simplevalue value = new simplevalue(original.gettable());                value.settypename("org.joda.time.contrib.hibernate.persistentdatetime");                value.settypeparameters(new properties());                value.setnullvalue(original.getnullvalue());                 iterator<column> coliter = original.getcolumniterator();                while(coliter.hasnext())                    value.addcolumn(coliter.next());                 property.setvalue(value);            }         }    } }

the above code works... not components not instances of persistentclass. tried following code handle components well... doesn't work when seems should.

public void customize(ejb3configuration config) {  iterator<persistentclass> itr = config.getclassmappings();    while(itr.hasnext()) {        persistentclass persistentclass = itr.next();        for(iterator<property> iter = persistentclass.getpropertyiterator(); iter.hasnext();) {            property property = iter.next();            if(property.gettype().getreturnedclass().equals(datetime.class)) {                simplevalue original = (simplevalue) property.getvalue();                simplevalue value = new simplevalue(original.gettable());                value.settypename("org.joda.time.contrib.hibernate.persistentdatetime");                value.settypeparameters(new properties());                value.setnullvalue(original.getnullvalue());                 iterator<column> coliter = original.getcolumniterator();                while(coliter.hasnext())                    value.addcolumn(coliter.next());                 property.setvalue(value);            } else if (property.getvalue() instanceof component) {                component c = (component)property.getvalue();                for(iterator<property> cit= c.getpropertyiterator(); cit.hasnext();) {                     property cproperty = cit.next();                     if(cproperty.gettype().getreturnedclass().equals(datetime.class)) {                          simplevalue original = (simplevalue) cproperty.getvalue();                          simplevalue value = new simplevalue(original.gettable());                          value.settypename("org.joda.time.contrib.hibernate.persistentdatetime");                          value.settypeparameters(new properties());                          value.setnullvalue(original.getnullvalue());                           iterator<column> coliter = original.getcolumniterator();                          while(coliter.hasnext())                              value.addcolumn(coliter.next());                           cproperty.setvalue(value);                     }                }             }         } }

i have tried tracing through hibernate code. seems hibernate somehow handles components differently persistentclasses can't seem figure out how. code above seems correctly set typename on component property hibernate never uses persistentdatetime usertype when datetime used inside @embeddable component. of course, if add @type annotation works. don't want have add annotation. want able bind usertype programmatically components same persistentclasses.

any insights?

thanks!


Comments

Post a Comment

Popular posts from this blog

javascript - Enclosure Memory Copies -

-
function myclass() { //lots , lots of vars , code here. this.bar = function() { //do numerous enclosed myclass vars } this.foo = function() { alert('hello'); //don't enclosed variables. } } each instance of myclass gets own copy of bar , foo, why prototyped methods use less memory. however, know more memory use of inner methods. it seems obvious me (1) below must true. agree? not distinct myclass instances have own distinct copies of bar, must have own distinct copies of myclass enclosure. (or else how bar method keep myclass variables straight on per instance basis?) now (2) question i'm after. since inner foo method doesn't use in myclass enclosure natural qustion is: javascript smart enough not keep myclass enclosure in memory use of foo? this depend entirely on implementation not language. naive implementations keep far more around others. answer true e.g. v8 (chrome's js engine) may not true spider...
Read more

php - Replacing tags in braces, even nested tags, with regex -

-
example preg_replace('/\{[a-za-z.,\(\)0-9]+\}/', 'replaced', 'lorem ipsum dolor sit {tag1({tag2()})}, consectetur adipiscing elit.'); the result: lorem ipsum dolor sit {tag1(replaced)}, consectetur adipiscing elit. question as can see "tag2" has been replaced, want replace "tag1" know how can this? (in cases might this: {tag1({tag2({tag3()})})}) , on.) btw using preg_replace_callback, easier show preg_replace here site can test code: http://www.spaweditor.com/scripts/regex/index.php you need add curly braces character set. here's pattern used: /\{[a-za-z.,\(\)\{\}0-9]+\}/ and here result: "lorem ipsum dolor sit replaced, consectetur adipiscing elit."
Read more